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  • Probability-if p (A) =1/3 ,P(B)=1/4, and P (AUB)=4/13, Find P(Aintersection B)

Probability-if p (A) =1/3 ,P(B)=1/4, and P (AUB)=4/13, Find P(Aintersection B)

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Given: P(A) =1/3, P(B)=1/4, P (AUB)=4/13,

P(A intersection B) = P(A) + P(B) - P (AUB)

                               = 1/3 + 1/4 - 4/13

                               = (52+39 - 4x12)/156

                              = (52 + 39 -48 )/156

                              = 43/156

 

Posted by

Ravindra Pindel

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