# Q.What is the point of intersection of medians of a triangle whose vertices are (-1,0), (5,-2) and (8,2). Please help anyone fasttttttttttttttttttttttttttttt.

$The\;point\;where\;medians\;intersect\;is\;called\;as\;centroid\\* Coordinates\;of\;centoird\;is\;calculated\;as\;average\;of\;all\;coordinates\\* Given\;points\;are\;(-1,0),\;(5,-2)\;and\;(8,2)\\*\Rightarrow x-coordinate=\frac{-1+5+8}{3}=\frac{12}{3}=4\\*\Rightarrow y-coordinate=\frac{0-2+2}{3}=0\\* So,\;point\;of\;intersection\;of\;median\;is\;(4,0)$

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