Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 ? resistor. What would be the readings in the ammeter and the voltmeter?

Answers (1)

The diagram is as shown :

Resistance of circuit =R=5+8+12=25 

Potential = 6V

V=IR

Rightarrow I=fracVR=frac625=0.24A

Now, for 12 ohm resistor, current = 0.24 A.

By Ohm's law,

                      V=IR=0.24	imes 12=2.88V

Reading of ammeter is o.24A and voltmeter is 2.88V.

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