savitri had to make a model of a cylindrical kaleidoscope for her science project . she wanted to use chart paper to make the curved surface of the kaleidoscope. what should be the area of chart paper required by her , if she wanted to make a kaleidosc

savitri had to make a model of a cylindrical kaleidoscope for her science project . she wanted to use chart paper to make the curved surface of the kaleidoscope. what should be the area of chart paper required by her , if she wanted to make a kaleidoscope of length 25 cm with a 3.5 cm radius ?

Answers (1)

D Deependra Verma

solution : We have ,

$r=$ Radius of the base of the cylinderical kaleidoscope = 3.5 cm

$h =$ Height (length ) of kaleidoscope = 25cm

$herefore$ Area of the chart paper required = Curved surface area of the kaleidoscope

$=$ $2pi rh=2 imes frac227 imes 3.5 imes 25 cm^2= 550 cm^2$