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  • savitri had to make a model of a cylindrical kaleidoscope for her science project . she wanted to use chart paper to make the curved surface of the kaleidoscope. what should be the area of chart paper required by her , if she wanted to make a kaleidosc

savitri had to make a model of a cylindrical kaleidoscope for her science project . she wanted to use chart paper to make the curved surface of the kaleidoscope. what should be the area of chart paper required by her , if she wanted to make a kaleidoscope of length 25 cm with a 3.5 cm radius ?

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solution :  We have , 

                r= Radius of the base of the cylinderical kaleidoscope = 3.5 cm 

                h = Height (length )  of kaleidoscope = 25cm 

herefore              Area of the chart paper required  = Curved surface area of the kaleidoscope 

                                                                      =     2pi rh=2 imes frac227 imes 3.5 imes 25 cm^2= 550 cm^2

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Deependra Verma

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