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Seca/1-sina=1+sina/cos^3aâ€‹

Answers (1)

$\frac{\sec a}{1- \sin a} = \frac{1+\sin a}{\cos ^3 a} \\ LHS = \frac{\sec a}{1- \sin a} \ \text{ multiply with (1+ sin a) in both numerator and denominator}\\ = \frac{1}{\cos a(1- \sin a)} \times \frac{1+\sin a}{1+ \sin a} \\ = \frac{1+\sin a}{\cos a(1 - \sin^2 a)} \\ = \frac{1+\sin a}{\cos^3 a} \\$

Hence proved

Posted by

Ravindra Pindel

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