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Show that the tangents drawn at the ends of a diameter of a circle are parallei.

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$Since;PQ;is; a; tangent; at; point; A\* OAperp PQ;;;;;;(tangent;at; A)\*Rightarrow angle OAQ=90^circ;;;;;;;..(1)\* Similarly,; OBperp RS\* Rightarrow angle OBS=90^circ;;;;;;;..(2)\* From;..(1);and;..(2),\* angle OAQ=angle OBS=90^circ\* i.e.,; angle BAP=angle ABS\* For;lines ;PQ ;& ;RS ;and ;transversal; AB\* angle BAP=angle ABS\* i.e., ;both ;alternate; angles ;are ;equal.\* So,; lines ;are ;parallel.\* herefore PQparallel RS.$

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Deependra Verma

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