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Simplify: tan^-1 ( acosx - bsinx /bcosx + asinx).

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Solution: We have ,

$an^-1(fracacos x-bsin xbcos x+asin x)$

$an^-1(fracacos x-bsin xbcos x+asin x)= an^-1(fracfracab- an x1+fracab an x)$

$Rightarrow$ $an^-1(fracacos x-bsin xbcos x+asin x)= an^-1fracab- an^-1( an x)= an^-1fracab-x$

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Deependra Verma

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