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Sketch the graphs showing variation of stopping potential with frequency of incident radiations for two photosensitive materials A and B Having threshold frequencies v_{A}> v_{B}\cdot
(i) In which case is the stopping potential more and why?
(ii) Does the slope of the graph depend on the nature of the material used?
Explain.

 

 

 

 
 
 
 
 

Answers (1)

Graph of variation of stopping potential with frequency is given below

(i) stopping potential is higher For B
Since

V_{0}= \left ( \frac{h}{e} \right )\upsilon -\frac{h\upsilon _{0}}{e}
Her

\upsilon _{0}_B< \upsilon _{0}_A
\because V_{0}\, for\, B> V_{0}\, for \, A
(ii) the slope of graph = \left ( \frac{h}{e} \right )= universal constant and does not depend on the nature of the material

Posted by

Safeer PP

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