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  • Solve: sin^2A-sinA=0 (0 ≤ A ≤ 180)

Solve: sin^2A-sinA=0 (0 ≤ A ≤ 180)

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\sin^2 A-\sin A =0 \\ \sin A (1-\sin A ) = 0 \\ \sin A = 0 \ or \ \sin A = 1 \\ A = \{ 0, \frac{\pi}{4}, \frac{3\pi}{4}, \pi\}

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Ravindra Pindel

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