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Solve the pair of equation 3x+2y_13=0 and 6x_4y_10=0 by ising substution method?

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eginarrayl	exttake the given equation as (1) and (2)\ 	extfrom (1), 3x=13-2y 	extand put x=frac(13-2y)3......left(3
ight) in equ(2),\ frac6(13-2y)3-4y-10=0\ Rightarrow 2(13-2y)-4y-10=0\ Rightarrow 26-4y-4y-10=0\ Rightarrow 16=8y\ Rightarrow y=2\ 	extPut y=2 	extin equation 3:\ x=fracleft(13-2	imes2
ight)3=frac93=3\ 	extSo, x=3;y=2endarray

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Deependra Verma

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