Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Sum of the areas of two squares is 544 m2. If the difference of their perimeters is 32 m, find the sides of the two squares.     

Sum of the areas of two squares is 544 m2. If the difference of their perimeters is 32 m, find the sides of the two squares. 

 

 

Answers (1)

\\ \text { Let 'a' and 'b' be the sides of two squares }\\ &\text { According to the question } \\ a^{2}+b^{2}=544 ....(i) \\ 4 a-4 b=32 \\ a-b=8 ....(ii) \\ \text{Put value of a from equation (i) in equation (ii)} \\ (b+8)^2 + b^2 = 544 \\ b^{2}+16 b +64+b^2 = 544 \\ b^{2}+8 b-240=0 \\ b^{2}+20b - 12b -240=0 \\ (b+20)(b-12)=0 \\ b=12 \mathrm{m} \\ \mathrm{a}=12+8=20 \mathrm{m} \\

Posted by

Safeer PP

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE Board Exam Dates 2027 LIVE: Class 10th, 12th subject-wise timetable soon at cbse.gov.in, LOC submission
anam-khan

CBSE Date Sheet 2027 LIVE: Class 10, 12 exam dates at cbse.gov.in soon; timetable, guidelines, updates

Latest Question