Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Sum of the areas of two squares is 544 m2. If the difference of their perimeters is 32 m, find the sides of the two squares.     

Sum of the areas of two squares is 544 m2. If the difference of their perimeters is 32 m, find the sides of the two squares. 

 

 

Answers (1)

\\ \text { Let 'a' and 'b' be the sides of two squares }\\ &\text { According to the question } \\ a^{2}+b^{2}=544 ....(i) \\ 4 a-4 b=32 \\ a-b=8 ....(ii) \\ \text{Put value of a from equation (i) in equation (ii)} \\ (b+8)^2 + b^2 = 544 \\ b^{2}+16 b +64+b^2 = 544 \\ b^{2}+8 b-240=0 \\ b^{2}+20b - 12b -240=0 \\ (b+20)(b-12)=0 \\ b=12 \mathrm{m} \\ \mathrm{a}=12+8=20 \mathrm{m} \\

Posted by

Safeer PP

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE third language policy throws French, Spanish, German teachers across schools into crisis
anam-khan

6.68 lakh register for CBSE Class 10 second board exams 2026
anam-khan

CBSE Class 10 second exam 2026 date sheet out; check timetable here

Latest Question