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  • Suppose a+b=198 and the equation x^2+ax+b=0 has positive integral roots ,then

Suppose a+b=198 and the equation x^2+ax+b=0 has positive integral roots ,then

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Solution:      Let  x_1 and x_2 be the roots x^2+ax+b=0

         Then

        Rightarrow    (x_1+x_2)=-a  and(x_1cdot x_2)=b

       Rightarrow       b+a+1=199  

     As 199 is prime x_1-1=1  or x_2-1=1

     x_1=2   then x_2=200

  herefore      a=-202  and b=400

Posted by

Deependra Verma

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