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The average of 11 innings played by a player is 50 the average of first 6 innings is 49 and that of last six is 52 find the sixth result 

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Average of all 11 innings =50, so sum \(=11 \times 50=550\)
Average of first 6 innings =49, so sum \(=6 \times 49=294\)
Average of last 6 innings =52, so sum \(=6 \times 52=312\)

Total sum: \text { Total sum }=\text { Sum of first } 5 \text { innings }+I_6+\text { Sum of last } 5 \text { innings }

\begin{gathered} 550=\left(294-I_6\right)+I_6+\left(312-I_6\right) \\ 550=606-I_6 \\ I_6=606-550=56 \end{gathered}

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Divya Sharma

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