# The circumference of the base of a cylindrical vessel is 132cm and its height is 25 cm . How many liters of water can it hold ?

Solution:  Let the base radius of the cylindrical vessel be $r$ and its height be $h$ .

We have ,

Circumference of the base $=$ 132cm and Height $=$ 25cm

$\therefore$             $2\pi r = 132$      and    $h=25$

$\Rightarrow$             $2\times \frac{22}{7}\times r=132$       and   $h=25$

$\Rightarrow$             $r=\frac{132\times7}{2\times22}=21$        and    $h= 25$

$\therefore$             Volume of the vessel $= \pi r^2h$

$=\frac{22}{7}\times(21)^2 \times25 cm^3=34650cm^3$

$= \frac{34650}{1000}litres=34.65litres$              $[\because 1000cm^3=1 litres]$

Hence , the vessel can hold 34.65 litres of water .

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