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  • The de-Broglie’s wavelength of electron present in first Bohr orbit of ‘H’ atom is :

The de-Broglie’s wavelength of electron present in first Bohr orbit of ‘H’ atom is :

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\begin{aligned} &\lambda_n=\frac{2 \pi r_n}{n}\\ &\begin{aligned} & =0.529 \AA=0.529 \times 10^{-10} m \\ & \\ & \lambda=2 \pi r_1=2 \pi \times 0.529 \times 10^{-10} \\ & \quad \lambda \approx 3.32 \times 10^{-10} m=3.32 \AA \end{aligned} \end{aligned}

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Divya Sharma

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