Let the numerator be x and the denominator be y
So, y=1+x as per question
Now, subtracting 1 from both numerator and denominator, we get
(x-1)/(y-1)=1/2
Or, 2x-2=y-1
Or, 2x-y=2-1
Or, 2x-y=1
Now substituting the value of y from the first eqn
2x-(1+x)=1
Or, 2x-1-x=1
Or, 2x-x=2
or, x=2
Again substituting the value of x in eqn 1
y=x+1
y= 2+1
y=3
Therefore the fraction is 2/3