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The figure shows a network of five capacitors connected to a 100 V supply. Calculate the total energy stored in the network.

 

 
 
 

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Let us calculate the Equivalent Capacitance, the Equivalent Capacitance of two 3\mu F Capacitor in parallel

C_{1}=3+3=6\mu F

Similarly, equivalent Capacitance of 1\mu F and 2\mu Fin parallel.

C_{2}=1+2=3\mu F

Now, the equivalent Capacitance of C_{1} and C_{2}in series:

C_{12}=\frac{6\times 3}{6+3}=2\mu F

Hence, the net Capacitance will be:-

C=2+2=4\mu F

Now, the energy stored in the network:-

F=\frac{1}{2}Cv^{2}=\frac{1}{2}\times 4\times 10^{-6}\times (100)^{2}=0.02\; J

Posted by

Safeer PP

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