The first angle of a triangle is 2 deggre more than the third angle and second angle is 6 deggre less than twice of third angle. Find the angles?.

$\begin{array}{l}\text{As we know, sum of all angle in trangle is }180^{\circ}.\\ \text{Let, angles of trangle is}\ A,\ B\ \&\ C.\\ \text{Given in question, }\\ A=C+2\ \&\ B=2C-6\\ A+B+C=180^{\circ}\\ \text{Now , we can put the values in equcation}\\ C+2+2C-6+C=180^{\circ}\\ \Rightarrow4C=184^{\circ}\\ \Rightarrow C=46^{\circ}\\ A=C+2^{\circ}=46^{\circ}\ +2\ ^{\circ}\ =48\ ^{\circ}\\ B=2C-6^{\circ}=2\times46^{\circ}\ -6\ ^{\circ}\ =86\ ^{\circ}\\ \text{Angles are }\ 48\ ^{\circ},86\ ^{\circ}\ ,\ 46^{\circ}.\end{array}$

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