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The first term of an $AP$ is $p$ and the common difference is $q$ , then its $10^{th}$ term is
Option:1 $q+9p$
Option:2 $p-9q$
Option:3 $p+9q$
Option:4 $2p+9q$

Answers (1)

$a_n=a+(n-1)d$

Here the first term a=p and the comment difference d=q. Therefore the tenth term

$a_{10}=p+(10-1)q=p+9q$

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