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  • The LCM of two numbers is 182 and their HCF is 13. If one of the numbers is 26, find the other.    

The LCM of two numbers is 182 and their HCF is 13. If one of the numbers is 26, find the other.

 

 

Answers (1)

 \\$ We know that $ \\ LCM (a,b) \times HCF(a,b) = a \times b \\ $ Given LCM = 182, HCF = 13, a =26 $\\\\ $ Other number = $ \frac{182 \times 13}{26} = 91

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