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The median of the following data is 

Class: 0-100 100-200 200-300 300-400 400-500 500-600 600-700 700-800 800-900 900-1000
Frequency: 2 5 x 12 17 20 y 9 7 4

525. Find the values of x and y, if total frequency is 100 :

 

 

 
 
 
 
 

Answers (1)

 

Class Frequency Cumulative frequency
0-100 2 2
100-200 5 7
200-300 x 7+x
300-400 12 19+x
400-500 17 36+x
500-600 20 56+x
600-700 y 56+x+y
700-800 9 65+x+y
800-900 7 72+x+y
900-100 4 76+x+y

500-600 is the median class.

\\76+x+y=100\\x+y=24......(1)

\\median=l+\frac{n/2-cf}{f}\times h\\\\=500+\frac{50-36-x}{20}\times100\\\\525==500+5(14-x)\\25=70-5x\\5x=45\\x=9\\\text{from(1)}\\y=15

Posted by

Safeer PP

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