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The minimum value of sum of real no a-^5,a^-4,3a^-3, 1, a^8 and a^10,with a>0,is

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best_answer

Solution: The given numbers are

a^-5,a^-4, a^-3, a^-3, a^-3, 1, a^8 ;and;a^10

We know that

AMgeq GM\ \Rightarrow 1/8(a^-5+a^-4+a^-3+a^-3+a^-3+a^0+a^8+a^10)geq [(a^-5	imes a^-4	imes a^-3	imes a^-3	imes a^-3	imes a^0	imes a^8	imes a^10)]^1/8geq 1

The Minimum value is 8

Posted by

Deependra Verma

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