Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

The number of solutions of the equation sin ( pi x/2square root 3)=x^2-2 square root 3+4 is .

Answers (1)

best_answer

Solution: $sin(pi x/2sqrt3)=(x-sqrt3)^2+1geq 1$

But $sin(pi x/2sqrt3)=leq 1.$ Thus $sin(pi x/2sqrt3)=1$

Therefore , $x=sqrt3$

Posted by

Deependra Verma

View full answer

Similar Questions

____________ and ___________ were the leaders of Santhal rebellion, which was against the ___________
Are the following pairs of sets equal? Give reasons. A = 2, 3, B = x: x is a solution of x^2+5x+6=0
At what point of the parabola x^2 = 9y is the abscissa three times that of ordinate?

Latest Question