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The resistance of a 0.1 N solution of acetic acid is 250  when measured in a cell of cell constant 1.15 cm-1. The equivalent conductance (in ohm-1 cm2 eq-1) of 0.1 N acetic acid is:

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Given:

  • R = 250 ohms
  • Cell constant = 1.15 cm-1
  • N = 0.1 N

Solution:

Conductivity, κ = Cell constant / R

= 1.15 / 250

= 0.0046 ohm-1 cm-1

Equivalent conductance, Λeq = (1000 × κ) / N

= (1000 × 0.0046) / 0.1

= 460 ohm-1 cm2 eq-1

Posted by

Saniya Khatri

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