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The second overtone of an open pipe has the same frequency as the first overtone of a closed pipe of 2 m long. The length of the open pipe is, .............. ?

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\text {Frequency of second overtone of open organ pipe }=\frac{3 v}{2 l}$\\ And Frequency of First overtone of closed pipe $=\frac{3 v}{4 L}$ \\Hence $\frac{3 v}{2 l}=\frac{3 v}{4 L}$ $\Longrightarrow L=\frac{l}{2}$ $\Longrightarrow l=2 L=2*2=4 \ m $

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