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The square root of (x^2+8x+15) (x^2+x-6) (x^2+3x-10)

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$=\sqrt{(x^2+8x+15) (x^2+x-6) (x^2+3x-10) }\\\\ =\sqrt{(x^2+5x + 3x+15) (x^2+3x -2x -6) (x^2+5x -2x-10)} \\\\ =\sqrt{[x(x+5) + 3(x+5)][ x(x+3) -2 (x+3)] [x(x+5) -2 (x +5)]}\\\\ =\sqrt{(x+5)(x+3)(x+3)(x-2)(x+5)(x-2)}\\\\ =\sqrt{(x+5)^2(x+3)^2(x-2)^2}\\\\ =(x+5)(x+3)(x-2)$

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Ravindra Pindel

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