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The sum of the length,breadth and height of a cuboid is 38cm and the length of its diagonal is 22cm. Find the surface area of cuboid.

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eginarrayl	extGiven 	extLengthleft(l
ight)+	extbreadthleft(w
ight)+	extheightleft(h
ight)=38 cm\ 	extDiagonalleft(d
ight)=22 cm\ 	extSurface area of Cuboid left(s
ight)=?\ 	extWe know, d=sqrtleft(l^2+w^2+h^2
ight)Rightarrow d=sqrtleft(l+w+h
ight)^2-2left(lw+wh+hl
ight)\ 22=sqrt38^2-2left(lw+wh+hl
ight)Rightarrow22^2=38^2-2left(lw+wh+hl
ight)\ 2left(lw+wh+hl
ight)=960\ 	extSince s=2left(lw+wh+hl
ight)Rightarrow s=960 cm^2endarray

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Deependra Verma

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