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The value of $x$ for which $2x,(x+10)$ and $(3x+2)$ are the three consecutive terms of an $AP$ , is
Option: 1 $6$
Option: 2 $-6$
Option: 3 $18$
Option: 4 $-18$

Answers (1)

$2x,\ x+10,\ 3x+2$ are three consecutive terms. There fore

$\\x+10-2x=3x+2-(x+10)\\10-x=2x-8\\3x=18\\x=\frac{18}{3}=6$

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