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The value of $k$ for which the system of equations $x+y-4=0$ and $2x+ky=3$ . has no solution, is

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For no solution

$\frac{a_1}{a_2}=\frac{b_1}{a_2}\neq\frac{c_1}{c_2}$

That is

$\frac{1}{2}=\frac{1}{k}\neq\frac{-4}{-3}$

$k=2\ and k\neq\frac{4}{3}$

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Safeer PP

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