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  • The value of the definite integral x cos x , where Lower limit =0 & upper limit =pi/2

The value of the definite integral x cos x , where Lower limit =0 & upper limit =pi/2

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Solution: We have ,

                I=int_0^pi/2xcos xhspace0.1cmdx

            We know that ,     int_0^af(x)dx=int_0^af(a-x)dx

         Hence ,    I=int_0^pi/2xcos xdx=fracpi2-1

Posted by

Deependra Verma

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