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Two coherent light waves of intensity $5 \times 10^{-2} Wm^{-2}$ each super-impose and produce the interference pattern on a screen. At a point where the path difference between the waves is $\frac{\lambda }{6}$ , $\lambda$ being wavelength of the wave, find the

(a) phase difference between the waves. (b) resultant intensity at the point. (c) resultant intensity in terms of the intensity at the maximum

Answers (1)

a)

$\phi=\frac{2\pi}{\lambda}\times\frac{\lambda}{6}=\frac{\pi}{3}$

b)

$\\I=I_1+I_2+2\sqrt{I_1I_2}cos\phi\\=3\times I_1=15\times10^{-2}W/m^2$

c)

$I_{max}=4I_1$

$I_{max}=4I/3$

$I=\frac{3}{4}I_{max}$

Posted by

Safeer PP

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