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Two conducting wires of the same material and of equal lengths and equal diameters are first connected in series and then parallel in a circuit across the same potential difference. The ratio of heat produced in series and parallel combinations would be

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If resistors are connected in parallel, the net resistance is given as 

                 frac1R_p=frac1R_1+frac1R_2

        Rightarrow frac1R_p=frac1R+frac1R

         Rightarrow frac1R_p=frac2R

          Rightarrow R_p=fracR2

If resistors are connected in series, the net resistance is given as 

                      Rightarrow R_s=R_1+R_2=R+R=2R

Heat produced = H = fracV^2Rt

fracH_sH_p=fracfracV^2t2RfracV^2tfracR2

Rightarrow fracH_sH_p=frac14

Rightarrow H_s:H_p=1:4

Thus, option C is correct.

Posted by

Deependra Verma

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