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  • Two dice are thrown together once. Find the probability of getting a sum of more than 9.       

Two dice are thrown together once. Find the probability of getting a sum of more than 9. 

 

 
 

Answers (1)

The possibile outcomes when two dies are thrown are

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1,6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2,6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3,6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4,6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5,6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6,6)

out of this 36 outcomes the sum is morethan 9 are {(4,6), (5,5), (5,6), (6,4), (6,5) and (6,6)}. That is 6. 

So the probability of getting a sum of more than 9 is 6/36=1/6

Posted by

Safeer PP

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