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Two point charge q1 and q2 at a separation r in vacuum exert a force on each other. what should be their separation in an oil of a relative permitivity 16 so that force between them remains same

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\\ Here, F_{\text {air }}=\frac{q_{1} q_{2}}{4 \pi \epsilon_{0} d_{\text {air }}^{2}}$ and $F_{o i l}=\frac{q_{1} q_{2}}{4 \pi \epsilon_{r} \epsilon_{0} d_{o i l}^{2}}$ \\ According to question,\\ $F_{\text {air}}=F_{\text {oll}}$ \\ or $\frac{q_{1} q_{2}}{4 \pi \epsilon_{0} d_{a i r}^{2}}=\frac{q_{1} q_{2}}{4 \pi \epsilon_{r} \epsilon_{0} d_{o i l}^{2}}$ \\ or $\epsilon_{r} d_{\text {oil}}^{2}=d_{\text {air}}^{2}$ \\ or $d_{\text {oll }}^{2}=\frac{(r)^{2}}{16}$ \\ or $d_{\text {oil }}=\frac{r}{4}$

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shubham.krishnan

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