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  • Two trains A and B of length 400 m each are moving on two parallel tracks with a uniform speed of 72 km h-1 in the same direction, with A ahead of B. The driver of B decides to overake A and accelerates by 1 m s-2. If after 50 s, the guard of B just brush

Two trains A and B of length 400 m each are moving on two parallel tracks with a uniform speed of 72 km h-1 in the same direction, with A ahead of B. The driver of B decides to overake A and accelerates by 1 m s-2. If after 50 s, the guard of B just brushes past the driver of A, what was the original distance between them?

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\ extGiven, length of train =400 m$ \ $V _0=72 km h ^-1=72 imes frac518=20 m s ^-1$ \ Acceleration $a =1 m s ^-2$ and $t =50 s$ \ Relative velocity of train $B$ with respect to $A =0$ \ Distance can be calculated as follows: \ $X=v_0 t+frac12 a t^2$ \ $=0+frac12 imes 1 imes 50^2$ \ $=1250 m$ \ Original distance $=1250-800=450 m$ (Because total length of two trains $=800 m )\ extRelative speed of ejected product =1500 km h ^-1$ \ So, actual speed of ejected product $=1500-500=1000 km h ^-1

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Deependra Verma

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