Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Using integration, find the area of the parabola y2 = 4ax bounded by its latus rectum.       <div style="float:left; width

Using integration, find the area of the parabola y2 = 4ax bounded by its latus rectum.

 

 
 
 
 
 

Answers (1)

Parabola: y^2= 4ax....(i)

Latus ractum: x=a

Intersection Point 

Put x =a in equation (i)

\\ y^2 = 4a^2 \\ y = \pm 2a

Intersection Point A(a,2a), B(a,-2a)

\\ $Required Area $ = 2 $Area of AOM$ \\ \\ = 2\int _0^{a} \sqrt{4ax}dx \\\\ = 2 \times \frac{2}{3 \times 4a} \left[(4ax)^\frac{3}{2}\right]_0^{a}\\\\ = \frac{8}{3}a^2

 

Posted by

Safeer PP

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

‘You ruined my career’: Students hit back at CBSE over 'abrupt' removal of additional subjects
anam-khan

‘Careers are at stake’: CBSE removes additional subject option for private students without prior notice
anam-khan

CBSE eases APAAR ID mandate for board exams 2026 over lack of parental consent, technical issues

Latest Question