Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • School
  • Using integration, find the area of the region enclosed by the parabola  and the line <img alt="3x - y + 6 = 0." src="https://learn.careers360.com/latex

Using integration, find the area of the region enclosed by the parabola y = 3x^{2} and the line 3x - y + 6 = 0.

 

Answers (1)

 y = 3x^{2} and the line 3x - y + 6 = 0.

Required Area = Area of AOB

Point A (-1,3)

Point B(2,12)

\\$Area$ = \int _{-1}^{2}(3x+6 - \sqrt{3}x)dx \\\\ = [\frac{3}{2}x^2+6x - \frac{\sqrt{3}}{2}x^2]_{-1}^2 \\\\ = (\frac{3}{2} - \frac{\sqrt{3}}{2})(4-1) + 6(2+1) \\\\ = \frac{3}{2}(3-\sqrt{3})+18 \ sq \ unit.

Posted by

Safeer PP

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Supplementary Exam 2025: Registrations open for Class 10, 12 private students today
anam-khan

CBSE opens application to access 10th answer scripts; verification, revaluation for Class 12 starts on May 31
anam-khan

CBSE supplementary exams 2025 from July 15; form submission starts on May 30

Latest Question