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Using Kirchhoff ’s rules, calculate the current (Ig ) that flows through the galvanometer of resistance 15 $\Omega$ in the circuit diagram shown in the figure

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$\\For \ BADB\\20I_1+3I_g-12I_2=0.......(1)$

$\\For \ BCDB\\2I_1-6I_g-I_2=0.......(2)\\For \ ADCEA\\13I_2+I_g=20........(3)$

$\\solving\\I_g=4.87mA$

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