Using remainder theorem,find the value of k so that (4k^2+kx-1) leaves the remainder 2 when divided by (x-3).

Answers (1)

Let p(x)=4x^2+kx-1
Here we are given that p(3)=2
i.e.,p(3)=4(3)^2+k(3)-1=2
Rightarrow 4*9+3k-1=2
Rightarrow 36+3k=3
Rightarrow 3k=-33
Rightarrow k=-11

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