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  • Water in a canal, 5·4 m wide and 1·8 m deep, is flowing with a speed of 25 km/hour. How much area can it irrigate in 40 minutes, if 10 cm of standing water is required for irrigation ?   <div style="float:left; width

Water in a canal, 5·4 m wide and 1·8 m deep, is flowing with a speed of 25 km/hour. How much area can it irrigate in 40 minutes, if 10 cm of standing water is required for irrigation ?

 

 

 

 
 
 
 
 

Answers (1)

Given :

Width of canal, b=5.4\; m

Depth of canal, h=1.8\; m

Speed of canal water =25\; km/hr=2500\; m/hr

In 40 mins there will be  2500\times \frac{40}{60}=\frac{5000}{3}\; \text{metre}  will be available for irrigation.

Hence,

the volume of water in canal = volume of land irrigated.

\Rightarrow \text{Volume of canal }=l\times b\times h

                                            =\frac{5000}{3}\times 5.4\times 1.8

Area of land irrigated if 10 cm standing water is there is equal to \left ( 5.4 \times 1.8 \times \frac{5000}{3} \right )\times \frac{10}{100}\; m^2

Area of land =16,20,000\; m^2                           

Posted by

Ravindra Pindel

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