What is the probability of getting 53 sundays in an year

Answers (1)

52 weeks*7 days per week = 364 days 
The remaining days in case of a leap year are 2 (366 - 364) 
The possibilities of these two days are (Sun,Mon),(Mon,Tue),(Tue,Wed),(Wed,Thu),... = 7 
The favorable outcomes = (Sun,Mon),(Sat,Sun) = 2 
Therefore the probability of getting 53 sundays in a leap year = 2/7 
The remaining day in case of a non leap year is 1 (365-364) 
The possibilities of this day are Sun, Mon, Tue, Wed, Thu, Fri, Sat = 7 
The favorable outcome = Sun = 1 
Therefore the probability of getting 53 sundays in a non leap year = 1/7

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