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(x-y)^2 + (x+y)^2 = 0 ; Find the value of 'y'.

Answers (1)

(x-y)2 + (x+y)2 = 0

x2 + y2 -2xy + x2 + y2 +2xy =0

2(x2 + y2) =0 

x2 + y2 =0

x=0 and y=0.

Posted by

Ravindra Pindel

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