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A sum of money under compound interest doubles itself in 4 years. In how many years will it become 16 times itself? 

 

Option: 1

12 years


Option: 2

16 years


Option: 3

8 years


Option: 4

None of these


It will take 16 yrs 4+4+4+4=16

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Posted by

Tapas Kumar Behera

A certain loan amounts, under compound interest, compounded annually earns an interest of Rs.1980 in the second year and Rs.2178 in the third year. How much interest did it earn in the first year?

Option: 1

Rs.1600


Option: 2

Rs.1800


Option: 3

 Rs.1900


Option: 4

None of these

 


1800

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Posted by

Guru G

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The interest on a certain sum lent at compound interest, the interest being compounded annually, in the 2nd year is Rs.1200. The interest on it in the 3rd year is Rs 1440. Find the rate of interest per annum.

 

Option: 1

10%


Option: 2

15%


Option: 3

20%


Option: 4

 25% 

 


Interest of 2nd year = 1200

Interest of 3rd year = 1440 

Difference = 240 

In compound interest, interest in next year is calculated on previous year 

So, = 240 / 1200 x 100 = 20 % 

Increase in next year interest is what percent of the interest of previous year is = to the rate of interest

 

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Posted by

shivangi.shekhar

If Rs.2000 amounts to Rs.2880 in 2 years at compound interest, what is the rate of interest per annum if the interest is being compounded annually?

Option: 1

10%


Option: 2

20%


Option: 3

15%


Option: 4

25%


P = 2000, A = 2880, T = 2 years, R =?

A = P [1 + R/100] T

2880 = 2000 [1 + R/100]2

2880/2000 = [1+R/100]2

$\sqrt{ }(144 / 100)=1+\mathrm{R} / 100$

1.2 = 100+R/100

1.2 = 100 + R / 100 

R = 20 %

 

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Posted by

Ritika Harsh

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Find the compound interest earned on Rs.20000 for 2 years at 10% p.a. the interest being compounded annually.

Option: 1

Rs.2100


Option: 2

Rs.4200


Option: 3

Rs.6300


Option: 4

Rs.5600 

 


P = 20000

T = 2 years 

R = 10 % 

C.I = P (1 + R/100) T -P

= 2000 [1+ 10/100]2 – P

24200 – 20000

= 4200 

 

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Posted by

Suraj Bhandari

Find the compound interest on Rs. 5000 in 2 years at 4% per annum, the interest being compounded half yearly.

 

Option: 1

R 412.16


Option: 2

R 312.16


Option: 3

R 400.16


Option: 4

R 420.16

 


412.16

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Posted by

NARENDAR

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Ruchi invested Rs. 1600 at the rate of compound interest for 2 years. She got Rs. 1764 after the specified period. Find the rate of interest.

 

Option: 1

5%


Option: 2

3%


Option: 3

7%


Option: 4

10%


Here, $\mathrm{P}=\mathrm{R} 1600, n=2$ years, $\mathrm{A}=\mathrm{R} 1764$
Now, according to the formula,
$ \text { Amount }=\mathrm{P}\left(1+\frac{R}{100}\right)^n$
$1764=1600\left(1+\frac{R}{100}\right)^2$
$\Rightarrow \quad \frac{1764}{1600}=\left(\frac{100+R}{100}\right)^2 \quad \Rightarrow \quad\left(\frac{21}{20}\right)^2=\left(\frac{100+R}{100}\right)^2$
$\Rightarrow \quad \frac{100+R}{100}=\frac{21}{20} \quad \Rightarrow \quad 100+\mathrm{R}=\frac{21}{20} \times 100$
$\Rightarrow 100+R = 105$
$\therefore R = 105-100 = 5%$
 

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Posted by

Suraj Bhandari

24. Raju took a loan at 8% per annum simple interest for a period of 5 years. At the end of five years he paid Rs.10640 to clear his loan. How much loan did he take?

Option: 1

Rs.8500


Option: 2

Rs.8000


Option: 3

Rs.7700


Option: 4

Rs.7600


Because S.I is always equal in every year , so in 5 years with 8 % rate S.I 40 % of P

Amount is 40 % of P

Amount is $140 \%$ of $\mathrm{P}$ so, $\mathrm{p}$ is $(10640 / 140) \times 100=7600$

 

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Posted by

shivangi.shekhar

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A sum of money invested at simple interest amounts to Rs 2480 at the end of four years and Rs.4080 at the end of eight years. Find the principal.

Option: 1

Rs.2040


Option: 2

Rs.1480


Option: 3

Rs.1240


Option: 4

Rs.880


Amount after 4 years = 2480 Rs.

Amount after 8 years = 4080 Rs.

Difference = 1600 

Because interest is S.I , so it is equal for every year 

P = A – I 

2480 – 1600 = 880

 

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Posted by

sudhir.kumar

Find the compound interest on Rs. 8000 at 4% per annum for 2 years compounded annually

 

Option: 1

 R 652.80


Option: 2

R 452.80


Option: 3

R 652


Option: 4

R 552.80


Here, P = R 8000, R = 4%, Time = 2 years
Now, according to the formula,
 $\text { Amount }=\mathrm{P}\left(1+\frac{R}{100}\right)^n=8000\left(1+\frac{4}{100}\right)^2=8000 \times \frac{26}{25} \times \frac{26}{25}=\mathrm{R} 8652.80$
∴ CI = R (8652.80 – 8000) = R 652.80

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Posted by

Sanket Gandhi

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