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3.12 How much charge is required for the following reductions:

           (iii)MnO_{4}^{-}\ to\ Mn^{2+}\ ?

The given reaction can be written as:- 

                                         Mn^{+7}\ +\ 5e^- =\ Mn^{+2}

Thus charge required in above equation =\ 5F

                                                                = 5(96500)

                                                                = 482500\ C

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Posted by

Devendra Khairwa

3.12     How much charge is required for the following reductions:

             (ii)  1\ mol \ of\ Cu^{2+}\ to\ Cu?

The equation can be written as:-

                                                          Cu^{2+}\ +\ 2e^-\ =\ Cu

Thus charge required is  =\ 2F

                                        = 2(96500) = 193000\ C   

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Posted by

Devendra Khairwa

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3.12     How much charge is required for the following reductions:

              (i) 1\ mol\ of\ Al^{3+}\ to\ Al\ ?

The equation becomes :-

                                  Al^{+3}\ + 3e^-\ =\ Al

So required charge is 3F.

Q = n*96500

Q  =   3*96500  =  289500 C

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Posted by

Devendra Khairwa

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