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The octahedral complex \mathrm{CoSO_{4}Cl\cdot 5NH_{3}} exists in two isomeric forms \mathrm{x} and \mathrm{y} . Isomer \mathrm{x} reacts with \mathrm{AgNO_{3}} to give a while precipitate,but does not react with \mathrm{BaCl_{2}} . Isomer \mathrm{y} gives white precipitate with \mathrm{BaCl_{2}} but does not react with \mathrm{AgNO_{3}}.

Isomers \mathrm{x} and \mathrm{y} are

Option: 1

ionization isomers


Option: 2

linkage isomers


Option: 3

co-ordination isomers


Option: 4

solvate isomers


Ionization isomers have the same central metal ion; only the ligands exchange place with anion or neutral ion outside of the co-ordination complex. The sole difference between the two isomers is which ligands are attached to the central metal.

The X isomer of \mathrm{CoS{{O}_{4}}Cl\cdot 5\text{ N}{{\text{H}}_{3}}} is \mathrm{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}S{{O}_{4}} \right]Cl}and the Y isomer is \mathrm{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}Cl \right]S{{O}_{4}}}

Their reactions are as follows:

\mathrm{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}S{{O}_{4}} \right]Cl\text{ }\left( X \right)\text{ }\xrightarrow{AgN{{O}_{3}}}AgCl\downarrow \text{ (white ppt}\text{.)}}

\mathrm{\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}Cl \right]S{{O}_{4}}\text{ (Y) }\xrightarrow{BaC{{l}_{2}}}BaS{{O}_{4}}\downarrow \text{ (white ppt}\text{.)}}

The correct answer is Option A- Ionization isomers.

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Posted by

Gautam harsolia

In a one component second order reaction,if the concentration of the reactant is reduced to half , the rate

Option: 1

increases two times


Option: 2

increases four times


Option: 3

decreases to one half


Option: 4

decreases to one fourth


As we have learnt,

For a second order Reaction

\mathrm{Rate = k [Reactant]^2}

So when the [Reactant] is halved, rate will become one-fourths

Hence, the correct answer is Option (4)

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Posted by

Gautam harsolia

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When cell has stalled DNA replication fork, which checkpoint should be predominantly activated?

Option: 1

G1/S

 

Option: 2

G2/M

 

 

 

Option: 3

M

 

 

Option: 4

Both G2 M and M

 

G2/M should be activated as the cell has stalled DNA replication fork.

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Posted by

Ajit Kumar Dubey

 The following reaction occurs in the Blast Furnace where iron ore is reduced to iron metal : Fe2O3(s)+3 CO(g) 2 Fe(l)+3 CO2(g) Using the Le Chatelier’s principle, predict which one of the following will not disturb the equilibrium ?
Option: 1  Removal of CO
Option: 2  Removal of CO2
Option: 3 Addition of CO2
Option: 4 Addition of Fe2O3  
 

\\Fe_{2}O_{3}+3CO \leftrightharpoons 2Fe+3CO \\

According to Le Chatelier's principle change in concentration by changing the amount of reactant or product affect the equilibrium. However, the addition of solid reactant won't affect the concentration.

Therefore, addition of solid Fe2O???3 will not disturb the equilibrium. 

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Posted by

vishal kumar

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The ore that contains the metal in the form of fluoride is :
Option: 1 Cryolite
Option: 2 Malachite
Option: 3 Magnetite
Option: 4 Sphalerite
 

The formula of the ores -

1) Cryolite-Na_{3}AlF_{6}

[Contains the metal in the form of fluoride]

2) Malachite-\; CuCO_{3}.Cu\left ( OH \right )_{2}

3) Magnetite-Fe_{3}O_{4}

4) Sphalerite-ZnS

 

So, option 1 is correct.

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Posted by

Ritika Jonwal

The purest form of commercial iron is:
Option: 1 wrought iron
Option: 2 pig iron
Option: 3 scrap iron and pig iron
Option: 4 cast iron
 

The purest form of iron is wrought iron.

Therefore, Option(1) is correct.

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Posted by

Kuldeep Maurya

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Among the reactions (a)  - (d), the reaction(s) that does / do not occur in the blast furnace during the extraction of iron is / are :

(a)  CaO+SiO_{2}\rightarrow CaSiO_{3} (b)  3Fe_{2}O_{3}+CO\rightarrow 2Fe_{3}O_{4}+CO_{2} (c)  FeO+SiO_{2}\rightarrow FeSiO_{3} (d)  FeO\rightarrow Fe+\frac{1}{2}O_{2}
Option: 1 (C) and (D)

Option:2  (A)

Option: 3 (A) and (D)

Option: 4 (D)
 

D

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Posted by

Guru G

The refining method used when the metal and the impurities have low and high melting temperatures, respectively is:
Option: 1 vapour phase refining
Option: 2 distillation
Option: 3 liquation
Option: 4 zone refining
 

As we have learnt,

 

Liquation -

In this method, a low melting metal like a tin can be made to flow on a sloping surface. In this way, it is separated from higher melting impurities.

-

Liquation, a technique for separating constituents of ore, a metal or an alloy by partial melting. When the material is heated to a temperature where one of the constituents melts and the other remains solid, the liquid constituent can be drained off. 

 

Therefore, Option(3) is correct.

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Posted by

Ritika Jonwal

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The element that can be refind by distillation is :
 
Option: 1 nickel
Option: 2 zinc
Option: 3 tin  
Option: 4 gallium

Impure zinc is refined by the distillation method.

Therefore, the correct option is (2).

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Posted by

Kuldeep Maurya

The process of the clacination and roasting in metallurigical industries, respectively, can lead to:
Option: 1 Global warming and photochemical smog
Option: 2 Global warming and acid rain
Option: 3 Photochemical smog and ozone layer depletion
Option: 4 Photochemical somg and Global warming 

We know

Calcination Releases → CO2 → Global warming

Roasting Releases → SO2 → Acid Rain

The processes of calcination and roasting in metallurgical industries, respectively, can lead to Global warming and acid rain Due to the industrial processes SO2 gas is released which is responsible for acid rain & CO2 gas for global warming.

Therefore, the correct option is (2).

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Posted by

Kuldeep Maurya

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