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#### A certain loan amounts, under compound interest, compounded annually earns an interest of Rs.1980 in the second year and Rs.2178 in the third year. How much interest did it earn in the first year?Option: 1 Rs.1600Option: 2 Rs.1800Option: 3  Rs.1900Option: 4 None of these

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#### The distance between two stations A and B is 440 km. A train starts at 4 p.m. from A and move towards B at an average speed of 40 km/hr. Another train starts B at 5 p.m. and moves towards A at an average speed of 60 km/hr. How far from A will the two trains meet and at what time?Option: 1 200,8 p.m.Option: 2 300,9 p.m.Option: 3 200,9 p.m.Option: 4 300,8 p.m.

The sum of the distances covered by both trains should be equal to the total distance between the stations A and B: 40t+60(t−1)=44040t + 60(t - 1) = 44040t+60(t−1)=440

40t+60t−60=440
100t−60=440
100t=500
t=5

So, the trains will meet 5 hours after Train A starts from A.

Train A starts at 4 p.m. so 5 hours from 4 p.m. is 4 p.m. + 5 hours = 9 p.m.

The two trains will meet 200 km from A at 9 p.m.

Option 3: 200, 9 p.m.

#### PQ is a tunnel. A dog sits at the distance of 5/ 11 of PQ from P. The train whistle coming from any end of the tunnel would make the dog run. If a train approaches P and dog runs towards P the train would hit the dog at P. If the dog runs towards Q instead, it would hit the dog at Q. Find ratio of speed of train and dog?Option: 1 5:2Option: 2 16:5Option: 3 11:1Option: 4 34:3

Option 3 - 11:1

########            P____5_____¶______6_____Q

"¶" is the dog located inside the tunnel PQ and #####... is a train approaching to it.

Case 1 - Dog decides to reach point P

Distance covered by Dog - 5 parts and train reaches at P

Case 2 - Dog decides to run towards point Q

At the time train reaches to point P, the dog covers 5 parts in direction of Q. Now the left out part covered by dog will be 1 part towards Q .

At the time dog covers 1 part and reaches Q, train covers whole 11 parts of tunnel and reaches from P to Q.

So, 11 part of train is eual to the 1 part covered by the dog to reach Q.

Ratio of their speeds - Train:Dog = 11:1

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#### Read the passage below and answer the following questions.Cheating is considered a criminal offence under the Indian Penal Code. It is done to gain profit or advantage from another person by using some deceitful means. The person who deceives another knows for the fact that it would place the other person in an unfair situation. Cheating as an offence can be made punishable under Section 420 of the IPC. Scope of Section 415 Cheating is defined under Section 415 of the Indian Penal Code as whoever fraudulently or dishonestly deceives a person to induce that person to deliver a property to any person or to consent to retain any property. If a person intentionally induces a person to do or omit to do any act which he would not have done if he was not deceived to do so and the act has caused harm to that person in body, mind, reputation, or property, then the person who fraudulently, dishonestly or intentionally induced the other person is said to cheat. Any dishonest concealment of facts that can deceive a person to do an act that he would not have done otherwise is also cheating within the meaning of this section. Essential Ingredients of Cheating requires · deception of any person. Fraudulently or dishonestly inducing that person to deliver any property to any person or to consent that any person shall retain any property; or · intentionally inducing a person to do or omit to do anything which he would not do or omit if he were not so deceived, and the act or omission causes or is likely to cause damage or harm to that person in body, mind, reputation or property.Deceit– a tort arising from an untrue or false statement of facts which are made by a person, recklessly or knowingly, with an intention that it shall be acted upon by the other person, who would suffer damages as a result. Fraud – a false or untrue representation of the fact, that is made with the knowledge of its falsity or without the belief in its truth or a reckless statement that may or may not be true, with an intention to induce a person or individual to act independent of it with the result that the person acts on it and suffers damages and harm. In other words, it is a wrong act or criminal deception with an intention to result in financial or personal gain.Question :- D went to a moneylender, Z, for the loan. D intentionally pledges the gold article with Z taking the loan. D knows that the article is not made of gold. After a few days, D leaves the village. Decide.Option: 1 -Option: 2 D has committed cheating as well as fraud   Option: 3 D has not committed the offence of cheating   Option: 4 D has committed an act which is an offence of cheating as well as the tort of deceit

As per section 415 of IPC, D has intentionally pledged the gold article with Z, his intention is clearly to deceive Z and cause him financial loss hence D would be liable for the offence of Cheating. Actions of D are also held liable as a tort of deceit.

Hence option (d) is correct.

#### In angiosperm, the haploid, diploid and triploid structures of a fertilized embryo sac sequentially are:Option: 1 Synergids, Primary endosperm nucleus and zygoteOption: 2 Antipodals, synergids, and primary endosperm nucleusOption: 3 Synergids, Zygote and Primary endosperm nucleusOption: 4 Synergids, antipodals and Polar nuclei

The correct option is Option 3) Synergids, Zygote, and Primary endosperm nucleus.

In angiosperms, the fertilized embryo sac, which is the female gametophyte, contains various structures at different ploidy levels after fertilization. These structures include synergids, zygote, and the primary endosperm nucleus.

Synergids: Synergids are haploid cells found within the embryo sac. They are located at the micropylar end and play a role in guiding the pollen tube to the embryo sac during fertilization.

Zygote: After the pollen tube reaches the embryo sac and delivers the male gametes, fertilization occurs. The fusion of the sperm cell with the egg cell results in the formation of a zygote. The zygote is the first cell of the sporophytic generation and is diploid (2n) in ploidy.

Primary endosperm nucleus: The primary endosperm nucleus, also known as the central cell, is located at the center of the embryo sac. It contains two polar nuclei and is involved in the formation of endosperm. After fertilization, the primary endosperm nucleus undergoes triple fusion with one sperm cell, resulting in the formation of a triploid (3n) primary endosperm nucleus.

Therefore, the correct sequence of haploid, diploid, and triploid structures in a fertilized embryo sac is Synergids, Zygote, and Primary endosperm nucleus, as stated in Option 3.

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#### A massless string connects two pulley of masses ' $2 \mathrm{~kg}$' and '$1 \mathrm{~kg}$' respectively as shown in the figure.The heavier pulley is fixed and free to rotate about its central axis while the other is free to rotate as well as translate. Find the acceleration of the lower pulley if the system was released from the rest. [Given, $g=10 \mathrm{~m} / \mathrm{s}^2$]Option: 1 $\frac{4}{3} \mathrm{~gm} / \mathrm{s}^2$Option: 2 $\frac{3}{2} \mathrm{~gm} / \mathrm{s}^2$Option: 3 $\frac{3}{4} \mathrm{~gm} / \mathrm{s}^2$Option: 4 $\frac{2}{3} \mathrm{~gm} / \mathrm{s}^2$

Not understanding sir

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#### In a common base amplifier circuit, calculate the change in base current if that in the emitter current is $\mathrm{2mA\: and\: \alpha =0.98}$  Option: 1 Option: 2 Option: 3 Option: 4

$\mathrm{ \alpha=\frac{\Delta I_c}{\Delta I_e} \Rightarrow \Delta I_c=0.98 \times 2=1.96 \mathrm{~mA} }$

$\mathrm{ \Delta I_b=\Delta I_e-\Delta I_c=2-1.96=0.04 \mathrm{~mA}}$

Hence option 1 is correct.

#### In the experiment, calculate the acceleration due to gravity, By using simple pendulum, which have time period of 0.3 second is measured from time of 50 oscillation with a watch of one second resolution. When length is 5 cm known to 1 mm accuracy find accuracy in the 'g'Option: 1 15.33 %Option: 2 12.33 %Option: 3 13 %Option: 4 15.55 %

\begin{aligned} & T=2 \pi \sqrt{\frac{l}{g}} \\ & g=\frac{1}{4 \pi^2 l} \frac{T^2}{l}\Rightarrow \frac{\Delta g}{T}= \frac{2 \Delta T}{T}+\frac{\Delta l}{l} \\ & \frac{\Delta g}{g}=2 \times \frac{1}{50 \times 0.3}+\frac{1 \mathrm{~mm}}{5 \mathrm{~cm}} \\ & =0.1533 \\ & \frac{\Delta g}{g} \times 100=15.33 \% . \end{aligned}

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