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0.5 moles of gas, A and x moles of gas B exert a pressure of 200Pa in a container of volume 10 \mathrm{~m}^3  at 1000 K. Given R is the gas constant in \mathrm{Jk}^{-1} \mathrm{~mol}^{-1}, \mathrm{x}   is -

Option: 1

\mathrm{\frac{2 R}{4-R} }


Option: 2

\mathrm{\frac{4-R}{2 R} }


Option: 3

\mathrm{\frac{4+R}{2 R} }


Option: 4

\mathrm{\frac{2 R}{4+R}}


Answers (1)

best_answer

from the ideal gas equation,
\mathrm{P V=\sum n R T }..............(i)
On substituting the given values in equation (i) we get,
\mathrm{ 200 \times 10=\left(n_A+n_B\right) \times R \times 1000 }

\mathrm{0.5+x =\frac{2000 \times 10}{R \times 1000} }
\mathrm{\frac{1}{2}+x =\frac{2}{R} }
\mathrm{x =\frac{2}{R}-\frac{1}{2}=\frac{4-R}{2 R}}.
 

Posted by

Suraj Bhandari

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