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  • 1 g of a liquid is converted to vapour at pressure. If <img alt="10\; %" src="https:/

1 g of a liquid is converted to vapour at 3\times 10^{5}Pa pressure. If 10\; %of the heat supplied is used for increasing the volume by 1600\; cm^{3} during this phase change, then the increase in internal energy in the process will be:

Option: 1

432000 J


Option: 2

4320 J


Option: 3

4800 J


Option: 4

4.32 \times 10^{8}J


Answers (1)

best_answer

10 \% \text { of } \Delta \mathrm{Q}=\mathrm{P} \Delta \mathrm{V} \text { (W/D by gas) }

\begin{aligned} & \frac{\Delta Q}{10}=3 \times 10^5\left(1600 \times 10^{-6}\right) \\ & \Delta Q=4800 \mathrm{~J} \end{aligned}

Using the first law of the thermodynamics

\begin{aligned} & \Delta \mathrm{Q}=\Delta \mathrm{u}+\mathrm{W} \\ & \Delta \mathrm{Q}=\Delta \mathrm{u}+\frac{\Delta \mathrm{Q}}{10} \Rightarrow \Delta \mathrm{u}=\frac{9}{10} \Delta \mathrm{Q} \\ & \Delta \mathrm{u}=\frac{9}{10} \times 4800 \Rightarrow \Delta \mathrm{u}=4320 \mathrm{~J} \end{aligned}

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Deependra Verma

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