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  • 10.30 mg of is dissolved into a liter of sea water of density 1.03 g/mL. The concentration of <img alt="O_{2}" src="htt

10.30 mg of O_{2} is dissolved into a liter of sea water of density 1.03 g/mL. The concentration of O_{2} in ppm is

Option: 1

10


Option: 2

20


Option: 3

25


Option: 4

40


Answers (1)

best_answer

1030 \mathrm{\ g} \text { of sea water contains }=10.3 \times 10^{-3} \mathrm{\ g}

10^{6} \mathrm{gm} \text { of sea water contains }=\left(10.3 \times 10^{-3}\right) / 1030 \times 10^{6}

\mathrm{ppm\: =\: \frac{10.3\: x\: 10^{-3}}{1030}\: x\: 10^{6}}

Thus, the correct answer is 10.

Therefore, the correct option is (1).

Posted by

rishi.raj

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