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18 civil engineers and 20 electrical engineers are nominated for the final round of the inter college debate completion. But 2 among them cannot join as they are hospitalized. In how many ways can the team of 15 head count be made now?

Option: 1

\frac{36!}{13!23!}


Option: 2

\frac{10!}{7!14!}


Option: 3

\frac{31!}{7!24!}


Option: 4

Cannot be determined


Answers (1)

best_answer

Note the following:

  • The formula for the combination for the selection of the\mathrm{x} items from the \mathrm{y} different items is \mathrm{=^{y}C_{x}=\frac{y!}{x!\left ( y-x \right )!}}

  • The restricted combination for the selection of the \mathrm{r} items from the \mathrm{n}different items with \mathrm{k} particular things always excluded is \mathrm{=^{n-k}C_{r}}

Since 2 engineers must never be included in the team, the following is evident.

  • The number from which the restricted combination is to be made is \mathrm{=n-k=\left ( 18+20 \right )-2=36} .

  • The number with which the restricted combination is to be made is \mathrm{=r-k=15-2=13}

Therefore, the required restricted combination is

\mathrm{=^{n-k}C_{r}}

\mathrm{=^{36}C_{13}}

=\frac{36!}{13!23!}

 

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